Question

What is t to the Ninth Power over t to the seventh power equal to?

Answer 1

There is a rule for dividing two indices involving a common base.

\[a^m \div a^n = \frac{ a^m }{ a^n } = a^{m-n}\]
You can simply write it using the same base with the new index being the first power minus the second power.

Answer 2

$$\Huge \dfrac{t^9}{t^7}$$
$$\Huge= \dfrac{t^2•t^7}{t^7}$$
$$\Huge =\dfrac{t^2•\cancel{t^7}}{\cancel{t^7}}$$
$$\Huge=t^?$$

Answer 3

Really, nice illustration, skullpatrol!
I would do such that, but I am not so professional at using writing tools at Openstudy.
(large fonts, colours, underline, bold, highlight colours, etc)