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Mathematics 6 Online
OpenStudy (eliesaab):

Question in comment

OpenStudy (eliesaab):

OpenStudy (dumbcow):

total number of pos integers is product of all divisors that go into 5^3 and all divisors that go into 2^b 5^3 has 4 divisors ---> 5^0, 5^1, 5^2, 5^3 2^b then must have (b+1) divisors ----> 4(b+1) = 24 -----> b = 5

OpenStudy (eliesaab):

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