Question

help please i dont know what to do next when i integrate

heres my work

Answer 1

You can't factor x^2 + 1

Answer 2

\[\large 3\int\limits_{}^{}\frac{ x-1 }{ x^2 + 1 }dx + 2\int\limits_{}^{}\frac{ 1 }{ x^2 + 2 }dx=\]\[\large 3\int\limits\limits_{}^{}\left( \frac{ x }{ x^2 + 1 } - \frac{1 }{ x^2 + 1 } \right)dx + 2\int\limits\limits_{}^{}\frac{ 1 }{ x^2 + 2 }dx=\]\[\large 3\int\limits_{}^{}\frac{ x }{ x^2 + 1 }dx - 3\int\limits_{}^{}\frac{ 1 }{ x^2 + 1 }dx + 2\int\limits_{}^{}\frac{ 1 }{ x^2 + 2 }dx\]First you can use substitution, second and third are one of the inverse trig integrals

Answer 3

http://integral-table.com/downloads/single-page-integral-table.pdf see (8) and (9)

Answer 4

hmmm lol can you show me

Answer 5

Even the first one is on there, see (10)

Answer 6

the first one is