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Find the radius of a circle in which an inscribed square has a side of 8 inches. x =
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Use this to find D=2r , knowing that s=8 \[ D^2= 2 s^2 \] Then find \[ r=\frac D2\]
4sqrt2
|dw:1476108815215:dw| D is the diagonal of the square You can work it out from pythagoras - or use the well known fact that diagaonal of square = side * sqrt(2) (This is the same as @eliesaab said above - in a slightly different way) You can also see that D is the diameter of the circle - so the radius is D/2
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