Solve and graph the absolute value inequality: |2x + 1| ≤ 5.
number line with closed dots on negative 3 and 2 with shading going in the opposite directions.
number line with closed dots on negative 3 and 2 with shading in between.
number line with open dots on negative 3 and 2 with shading in between.
number line with closed dots on negative 2 and 2 with shading in between.
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OpenStudy (firechild17):
@AloneS
OpenStudy (brainzonly):
Solve and graph the absolute value inequality: |2x + 1| ≤ 5.
Make 2 equations:
2x+1 < 5 and 2x-1 < 5
alones (alones):
Bruhh this thing refreshed Smh..brainz fine you continue >.>
OpenStudy (brainzonly):
lol
OpenStudy (firechild17):
Its ok
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OpenStudy (brainzonly):
2x+1 < 5 and 2x-1 < 5
2x+1-1 < 5-1 and 2x-1+1 < 5+1
OpenStudy (brainzonly):
Which is:
2x < 4 and 2x < 6
OpenStudy (firechild17):
ok
OpenStudy (brainzonly):
Then…
2x/2 < 4/2 and 2x/2 < 6/2
Which is:
X is less than or equal to 2 AND x is equal to or less that 3.
OpenStudy (firechild17):
So its C?
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OpenStudy (brainzonly):
Written out: 2 > x < 3
Number line with closed dots ( because it may or may not be equal to 2 or 3) and shading in between, so yes 3. :)