Solve and graph the absolute value inequality: |2x + 1| ≤ 5. number line with closed dots on negative 3 and 2 with shading going in the opposite directions. number line with closed dots on negative 3 and 2 with shading in between. number line with open dots on negative 3 and 2 with shading in between. number line with closed dots on negative 2 and 2 with shading in between.
@AloneS
Solve and graph the absolute value inequality: |2x + 1| ≤ 5. Make 2 equations: 2x+1 < 5 and 2x-1 < 5
Bruhh this thing refreshed Smh..brainz fine you continue >.>
lol
Its ok
2x+1 < 5 and 2x-1 < 5 2x+1-1 < 5-1 and 2x-1+1 < 5+1
Which is: 2x < 4 and 2x < 6
ok
Then… 2x/2 < 4/2 and 2x/2 < 6/2 Which is: X is less than or equal to 2 AND x is equal to or less that 3.
So its C?
Written out: 2 > x < 3 Number line with closed dots ( because it may or may not be equal to 2 or 3) and shading in between, so yes 3. :)
C I mean XD
thanks
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