Question

let h(x)= 6x/cos x. Find h'(0)

Answer 1

First find the derivative of h(x)

Answer 2

Then plug in 0 for x and solve

Answer 3

how do you differentiate it?

Answer 4

Hey ChillPill!
Quotient rule, ya?\[\large\rm \left(\frac{6x}{\cos x}\right)'=\frac{(6x)'\cos x-6x(\cos x)'}{(\cos x)^2}\]

Answer 5

won't it be -sinx for the differentiation of the denominator?

Answer 6

\[\large\rm \left(\frac{6x}{\cos x}\right)'=\frac{(6x)'\cos x-6x(-\sin x)}{(\cos x)^2}\]Yes.