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OpenStudy (cameronlovesmorgan):
Solve 4(c + 2) < 4c + 10
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Directrix (directrix):
4(c + 2) < 4c + 10 4c + 8 < 4c + 10 The two 4c terms subtract off, leaving 8 < 10 which is a true statement. Any value of c will make this inequality true. The solution set is the set of all real numbers. @cameronlovesmorgan
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