Question

Evaluate 48 x a to the negative 3rd power for a = 2

8

6

One-Eighth

One-Sixth

Answer 1

\[48\times48\times48\times2\]

Answer 2

\(\huge\bf{48 \times 2^{-3}}\)

Thats how it looks right?

Answer 3

\(\huge\bf{a^{-b}=\frac{1}{a^{b}}}\)

So we plug in....

\(\huge\bf{2^{-3}=\frac{1}{2^{3}}}\)

Answer 4

So you would do....

\(\huge\bf{48 \times \frac{1}{2^{3}}}\)