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Algebra 12 Online
OpenStudy (needshelpdfdf):

x2 = 16

563blackghost (563blackghost):

Work backwards as before....instead of finding the square we find the square root of 16... \(\huge\bf{\sqrt{16}=x}\)

OpenStudy (mathmale):

First of all, it's important that you express exponentiation properly: x^2=16 (correct, clear) x2=16 (vague, mathematically incorrect)

OpenStudy (needshelpdfdf):

-4,4?

OpenStudy (alivejeremy):

Correct.

563blackghost (563blackghost):

Yes it would be 4 :)

OpenStudy (palsbhatt):

x= 4 or -4

OpenStudy (mathmale):

Please show HOW you obtained your answer. x^2=16 actually has TWO solutions. You must find both, and explain how you did that.

OpenStudy (mathmale):

"x= 4 or -4" is better, but can you explain how you obtained these results?

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