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Algebra
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x2 = 16
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Work backwards as before....instead of finding the square we find the square root of 16... \(\huge\bf{\sqrt{16}=x}\)
First of all, it's important that you express exponentiation properly: x^2=16 (correct, clear) x2=16 (vague, mathematically incorrect)
-4,4?
Correct.
Yes it would be 4 :)
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x= 4 or -4
Please show HOW you obtained your answer. x^2=16 actually has TWO solutions. You must find both, and explain how you did that.
"x= 4 or -4" is better, but can you explain how you obtained these results?
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