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Choose the equation that could be used to find two consecutive integers whose sum is 67. n + n = 67 n + (n + 2) = 67 n − (n + 1) = 67 n + (n + 1) = 67
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Any ideas?
Well, it's obviously not the third one because you want a sum. So you can rule that one out. Now, consecutive integers are integers in order (+1), such as 1, 2, 3, 4, ...
Recall: consecutive integers are numbers obtained by counting by ones from any number in the set of integers
and i can rule out the first one because there is no consecutive integers in that equation right?
Let n = any integer.
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The next consecutive integer obtained by counting by ones would be n + 1.
so it is the last one.
Correct.
find two consecutive integers whose sum is 67 $$\Huge n + (n+1) = 67$$
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