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For a 90 degree counterclockwise rotation you would use this rule... \(\huge\bf{(x,y) \rightarrow (-y,x)}\) So lets apply.... \(\huge\bf{J=(-4,1) \rightarrow (1,4)}\)
K' -2,4 L'-1, 3?
Correct :)
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THANK YOU!!!!!!!
So that is `J' K' L'` Now we need to find it with a reflection :)
Okay thank you a bunch.
Quite confused with second part though.
Yes it is, not sure how to do that.
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Maybe @3mar or @jiteshmeghwal9 can help you with the second part :) Im sorry but I have to go :(
Ok, cya
@3mar can you help
@firedragonrage
Well, I am here. How could I help you?
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