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What number must you add to complete the square? x^2 + 8x = -3 A. 16 B. 8 C. 4 D. 64
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Of course!
@3mar are you going to help or not?
I am !
As the coefficient of x^2 is unity, then we are going to add and subtract the half of the x-coefficient squared!
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uhh...
That means look at : \[(1)x^2\] then: \[ ( )x\] \[x^2+8x+(\frac{ 8 }{ 2 })^2-(\frac{ 8 }{ 2 })^2=-3\]
I'm still not comprehending
to get \[x^2+8x+16=(x+4)^2\] you must add 16 and subtract 16 easy now?
Partially...
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add 16 and subtract 16 don't change anything in one side of the equation!
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