Find the equation of the tangent line to
y = ln x
at
x = 1.

Question

Find the equation of the tangent line to 
y = ln x
 at 
x = 1.

mathmale · Answer

Writing the equation of a straight line requires that you first have the slope and one point on the line.  The point-slope form of the equation of a straight line is$$y-y _{1}=m(x-x _{1})$$
Substitue your values for m, x_1 and y_1 into this equation, and then simplify the equation.  Done.  Please show your work.

mathmale · Answer

Note:  In this problem, the slope of the tangent line is the derivative of y=ln x, evaluated at x=1.  Thus, x_1 is = to 1.  Using the formula y=ln x, calculate the value of y_1.