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OpenStudy (iwanttogotostanford):
@sshayer @steve816 @triciaal
OpenStudy (steve816):
No symmetry I believe.
OpenStudy (iwanttogotostanford):
@steve816
OpenStudy (iwanttogotostanford):
i need help with like 5 more if you please could :-)
OpenStudy (iwanttogotostanford):
@mathstudent55 @Nnesha
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OpenStudy (iwanttogotostanford):
@FaiqRaees
OpenStudy (iwanttogotostanford):
someone please i have so many questions
OpenStudy (iwanttogotostanford):
@calculusxy
OpenStudy (iwanttogotostanford):
@sshayer
OpenStudy (iwanttogotostanford):
@sshayer please help ASAP
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OpenStudy (sshayer):
if the asymptote is y=pm a/b x
and foci are (0,+-a)
then eq. of hyperbola is \[\frac{ y^2 }{ a^2 }-\frac{ x^2 }{ b^2 }=1\]
here foci is (0,+-4)
a=4
\[\frac{ a }{ b }=\frac{ 1 }{ 3 },\frac{ 4 }{ b }=\frac{ 1 }{ 3 },b=14\]
now you can write the eq.
OpenStudy (iwanttogotostanford):
oh xo it is B!!!
OpenStudy (iwanttogotostanford):
@sshayer
OpenStudy (sshayer):
what about A?
OpenStudy (sshayer):
correction
b=4*3=12
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OpenStudy (iwanttogotostanford):
A is right....
OpenStudy (iwanttogotostanford):
@Kevin can you help me with a couple math questions please??
OpenStudy (kevin):
Sorry, I just about to go sleep
OpenStudy (iwanttogotostanford):
just 1x please?
OpenStudy (kevin):
hmm.... tomorrow? xD
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OpenStudy (kevin):
let the other help u..
See you
OpenStudy (iwanttogotostanford):
@Will.H @Nnesha
OpenStudy (iwanttogotostanford):
@ajspeller
OpenStudy (iwanttogotostanford):
@triciaal
OpenStudy (triciaal):
strong suggestion
calm down and organize in groups by topic
open post with one of each kind
pay attention to the steps then apply to the others