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Physics 16 Online
OpenStudy (revircs):

The graph of a vs. m is an inverse power law. If a vs m^-1 is graphed, you will get a straight line. What does the slope of this graph show?

OpenStudy (revircs):

I have everything graphed out, but I have no idea what the graph of a vs m^-1 is supposed to tell me

OpenStudy (revircs):

This is about Newton's second law of motion. A weight is attached to a pulley and is pulling a cart.

OpenStudy (revircs):

Also for this one, there is a constant force of 10.3N

OpenStudy (revircs):

https://gyazo.com/52903432eba50e244d7797bbaff79a06 a vs m is on the left, and a vs m^-1 is on the left

OpenStudy (revircs):

https://gyazo.com/4956a1e8968bf73c5be4c351dcce543f and here is the raw data

ganeshie8 (ganeshie8):

\(\color{red}{F} = ma \implies a = \color{red}{F}*(1/m)\)

ganeshie8 (ganeshie8):

Compare that with the equation of straight line \[y = \color{red}{m}*x\]

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