A spaceship is moving at a speed of 0.84c away from an observer at rest. A boy in the spaceship shoots a proton gun with protons having a speed of 0.62c. What is the speed of the protons measured by the observer at rest when the gun is shot (a) away from the observer and (b) toward the observer?

Question

osprey · Answer

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ganeshie8 · Answer

$$u = \dfrac{u'+v}{1+u'v/c^2}$$


v = 0.84c
u' = 0.62c
c = speed of light