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Algebra 17 Online
OpenStudy (pxrson):

A survey was taken of students in math classes to find out how many hours per day students spend on social media. The survey results for the first-, second-, and third-period classes are as follows: First period: 2, 4, 3, 1, 0, 2, 1, 3, 1, 4, 9, 2, 4, 3, 0 Second period: 3, 2, 3, 1, 3, 4, 2, 4, 3, 1, 0, 2, 3, 1, 2 Third period: 4, 5, 3, 4, 2, 3, 4, 1, 8, 2, 3, 1, 0, 2, 1, 3 Which is the best measure of center for third period and why?

OpenStudy (pxrson):

When you do the IQR formula, it says that x<8.5, so technically it isn't an outlier. However, when you do a box plot w/ it, it's skewed to the right.

OpenStudy (pxrson):

WILL GIVE MEDAL AND FAN!!

OpenStudy (smartpanda1):

The numerical order is 0, 1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 8. There are a total of 17 numbers in the list. Count 8 numbers up (0,1, 1, 1, 2, 2, 2, 3, 3). The next number, 3, is the center, because 8 numbers surround it on each side.

OpenStudy (pxrson):

I apologize for not putting the answers they are: Interquartile range, because there is 1 outlier that affects the center Standard deviation, because there are no outliers that affect the center Mean, because there are no outliers that affect the center Median, because there is 1 outlier that affects the center

OpenStudy (smartpanda1):

Median = 3 This is the answer

OpenStudy (pxrson):

Oh, I thought it was mean because there are technically no outliers.

OpenStudy (smartpanda1):

there is an outlier, 8.

OpenStudy (smartpanda1):

btw will you medal and fan?

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