Question

A 50 kg crate is pulled at constant speed by a 100 N that acts 30 degrees above the horizontal. What is the coefficient of sliding friction?

Answer 1

net force = applied force - friction force
friction force = applied force - net force

\[net force = \sqrt{x^{2} + y^{2}}\]

x-component = 100 N cos 30
y-component = 100 N sin 30

The net force is 90 N.

I'm not really sure.

Answer 2

What's the mass for?

Answer 3

@mathmale