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Find the exact values of sin A and cos A. Write fractions in lowest terms. A right triangle ABC is shown. Leg AC has length 36, leg BC has length 48, and hypotenuse AB has length 60. sin A = three fifths; cos A = four fifths sin A = Afour thirds; cos A = three fourths sin A = five fourths; cos A = five thirds sin A = four fifths; cos A = three fifths
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This a right triangle in C. Sin A=36/60=3/5 How much is the Cos A
Sin =(opposite side)/Hypotenuse Cos=(adjacent side)/Hypotenuse
It is a right triangle since \[ 60^2=48^2+36^2=3600 \]
cos A = four fifths
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