I think I know the concept just a little confused on the answer.
When you know the VERTEX of a parabola, the best formula for the equation of the parabola to use is, appropriately enough, the "vertex formula:"\[y-k=a(x-h)^2\] for a vertical parabola.
You are given the coordinates of the vertex AND the coordinates of one point on the graph of the parabola. Substitute these numerical values into the equation given abov e and then determine the value of the constant coefficient, 'a.'
Since the vertex is at (-2,-1), h=-2 and k=-1. Since the given point is on the curve, x=-1 and y=1.
This is all the info you need with which to calculate the coefficient 'a.'
1-(-2)=a(-1-(-1))^2
I don't need to calculate anything I just need to write the equation
Try finding a now. We will check your answer once you have "a."
You do need to simplify the equation you've typed in. From it we will obtain the general equation (in vertex form) for this parabola.
Okay so the equation i typed in, is it correct so far teacher?
We will check your equation once you've finished finding "a."
\[y-k=a(x-h)^2\] is (again) the most general form of the vertex equation. Subst. the values of h, k and a. What equation do you obtain by doing so?
Solve for a: 1-(-2)=a(-1-(-1))^2
3-a(0)^2=0
So a=0? Unfortunately, that's not possible.
\[1-(-2)=a(-1-(-1))^2\] Looks like there's an arithmetic problem here.
\[y-k=a(x-h)^2\]
since the vertex is at (-2,-1), subst. -1 for k and -2 for h. Then\[y-(-1)=a(x-(-2))^2\]
Now the given point is (-1,1). Subst. -1 for x and 1 for y. Yes, I think you've already done these things, but let's be sure our equation for a is correct.
Okay lets make sure
I'm getting the same result as you: a=0. That could not possibly be true. Can you move on to another problem or do you have to type in some answer for this one first?
No its a assignment I can move on
I'd suggest you do that. I'm trying to find a solution to this problem in a different way.
Okay, Meanwhile I will try to work on the other problems, thanks
Anything yet?
@mathmale
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