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The denominator of a fraction is five more than twice the numerator. If both numerator and denominator are decreased by two, the simplified result is 1 3 . Find the original fraction. (Do NOT simplify.)
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I will say x/2x+5
fraction
hey welcome to os
So you have the original \(\Large \frac{ x }{ 2x+5}\) both numerator and denominator are decreased by two \(\Large \frac{ x -2 }{ 2x+5-2}\) result is 1/3: \(\Large \frac{ x -2 }{ 2x+5-2} =\frac{ 1 }{ 3} \) Solve for x; go back and plug into original fraction.
I don't know how to do that
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First simplify it, \(\Large \frac{ x -2 }{ 2x+3} =\frac{ 1 }{ 3}\) Then you can cross multiply to start
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