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Mathematics 10 Online
KjSaif (kjsaif):

Could you guys check my work :) Would appreciate it!

KjSaif (kjsaif):

OpenStudy (3mar):

May I help?

KjSaif (kjsaif):

yes

OpenStudy (3mar):

Thank you.

OpenStudy (mrnood):

The rate is simply the slope of the graph since it passes through the origing it is simple to calculate "rise/run" or "delta Y /delta x" or (y2-y1)/(x2-x1)

OpenStudy (3mar):

Do you know hoe to get the slope (rate of change) of the this function/line?

KjSaif (kjsaif):

yes i believe so

OpenStudy (mrnood):

@KJSaif so is that how you got your answer of 0.4 if so - do you have any reason to doubt yourself?

KjSaif (kjsaif):

no

OpenStudy (mrnood):

Well done :-)

KjSaif (kjsaif):

Thanks :)

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