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Mathematics 7 Online
zarkam21 (zarkam21):

Help with this then I think I can do the rest

zarkam21 (zarkam21):

zarkam21 (zarkam21):

Help with only one question, then I will try the other one by myself

Directrix (directrix):

Which one do you want to do now?

Directrix (directrix):

@zarkam21 ^^^^ Which on now?

zarkam21 (zarkam21):

First one

Directrix (directrix):

y = 2x x² + y² = 15 ------------ These are the equations of a line and a circle. We can expect 0, 1, or 2 answers.

Directrix (directrix):

In x² + y² = 15, substitute 2x for y because the first equation is y = 2x.

Directrix (directrix):

x² + (2x)² = 15 x² + 4x² = 15 5x² = 15 x² = 3 x = +√ 3 and x = - √ 3

Directrix (directrix):

For each of the two x values, solve for the corresponding y value in the first equation. y = 2x Let x = +√3 y = 2 * +√ 3 = 2 √3

Directrix (directrix):

y = 2x Let x = - √3 y = 2 * - √3 = -2√3

Directrix (directrix):

Solution Coordinates are: (√3 , 2 √3) and (- √3 , -2√3)

zarkam21 (zarkam21):

So the solutions are (√3 , 2 √3) and (- √3 , -2√3)

zarkam21 (zarkam21):

For the first problem

Directrix (directrix):

Here's a graph of our work.

Directrix (directrix):

See it "live" here: http://www.wolframalpha.com/input/?i=y+%3D+2x,+x%C2%B2+%2B+y%C2%B2+%3D+15

Directrix (directrix):

>>> So the solutions are (√3 , 2 √3) and (- √3 , -2√3) Yes

zarkam21 (zarkam21):

Oh okay thanks so much! =)

Directrix (directrix):

You are welcome. Your problem (second one) is quite similar to this.

zarkam21 (zarkam21):

Yes, I got the answer for that one as well as a couple other ones. Thanks again for all of your help, I really appreciate it. =)

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