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asdfghjkl h e l p Solve: 32x^2 - 40x - 12 = -8x + 12
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x=-0.5
sorry- but i forgot to mention its quadratic equations :< and there's supposed to be two answers-- i t h i n k
oh then idk @KJSaif
\[x=\frac{ -1 }{ 2 }\\] and\[x=\frac{ 3 }{ 2 }\]
-1/2 and 3/2
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thankyou ! But how do i exactly reach the the answers...?
im glad you asked :)
Step 1: Subtract -8x+12 from both sides. 32x2−40x−12−(−8x+12)=−8x+12−(−8x+12) 32x2−32x−24=0 Step 2: Factor left side of equation. 8(2x+1)(2x−3)=0 Step 3: Set factors equal to 0. 2x+1=0 or 2x−3=0
good job kjsaif!
Thanks @Idkanything
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i just knew only 1 answer
@KJSaif
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