Algebra
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OpenStudy (paomar97):
what's the value of y in x=(sqrt(y)+6)/(7-sqrt(y)) ?
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OpenStudy (3mar):
Well, I am here.
OpenStudy (paomar97):
Thanks!
OpenStudy (3mar):
Welcome back!
OpenStudy (3mar):
Do you know how to separate y?
OpenStudy (paomar97):
I am trying to find the inverse of the function! I already did some steps but i'm stuck!
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OpenStudy (paomar97):
Yes but not this one!
OpenStudy (paomar97):
OpenStudy (paomar97):
I sent a picture
OpenStudy (3mar):
I got it!
OpenStudy (3mar):
But why you use an online sites to find the inverse?
Can not you do it yourself?
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OpenStudy (paomar97):
I tried but I can't! I used mathway and wolgramalpha but the answers were not in the same format i need
OpenStudy (paomar97):
Do you know the answer?
OpenStudy (3mar):
Ok
Can we do it together now?
easy and fast!
OpenStudy (paomar97):
Yes!
OpenStudy (3mar):
Let' start
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OpenStudy (3mar):
Can you cross multiply this fraction?
OpenStudy (paomar97):
I think so!
OpenStudy (3mar):
Show me, please!
OpenStudy (paomar97):
6/7
OpenStudy (3mar):
How is that?
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OpenStudy (paomar97):
the square roots cancel
OpenStudy (3mar):
nonononon
OpenStudy (paomar97):
ohhh right
it's addition so I can't
OpenStudy (paomar97):
I have to rationalize the denominator?
OpenStudy (3mar):
Yes.
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OpenStudy (3mar):
x=(sqrt(y)+6)/(7-sqrt(y))
this is the form you give. roght?
OpenStudy (3mar):
right?
OpenStudy (paomar97):
right!
OpenStudy (3mar):
ok
\[x={\frac{ \sqrt(y)+6 }{ 7-\sqrt(y) }}\]
is that correct?
OpenStudy (paomar97):
yes
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OpenStudy (3mar):
Great!
OpenStudy (3mar):
Now cross multi.
OpenStudy (3mar):
@paomar97
Are you there?
OpenStudy (mrnood):
@3mar
I'd like to see this if poss?
It looks to me that you would always have a term with yx in it
OpenStudy (3mar):
Don't you know it?
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OpenStudy (3mar):
you can fisrtly cross multi, then simplify
OpenStudy (3mar):
then collect all sqrt(y) in one side then simplify
OpenStudy (3mar):
after that square both sides
likeabossssssss (likeabossssssss):
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