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Heeeeelp Pls.
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Can someone help me with the first two? D:
@zepdrix @mathmate
9th one is 1/7 , sqrt((n+2)/(49n+2))=sqrt((1+2/n)/(49+2/n))
How'd you get that?
Why did you divide by n?
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lim 1/n=0 so to apply this formula i put it in that form
Oh i see. thanks! Do you know $8?
#8*
For 8th one, 4^(n+2)=16 4^n
so its basically 16 (4/5)^n
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4/5 <1 so by its convergent, its basically a GP series
how'd you get 16 4^n ?
4^(n+2)= 4^n. 4^2 =16. 4^n
Got it thanks
Can you help me with these? I am stuck :/
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I got #13.
I thought #14 was 1, it wasn't...
which one is 13?
hello
I got #14 as well #13 was 1 #14 was 0
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I dont get # 12 though
12 will be 1
How did you get that?
Ooooooh. Thanks!
lim cos(3/n)=cos (lim3/n)=cos 0 =1
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I needz help with number 18 :3
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