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Mathematics 16 Online
OpenStudy (itz_sid):

Heeeeelp Pls.

OpenStudy (itz_sid):

Can someone help me with the first two? D:

OpenStudy (itz_sid):

@zepdrix @mathmate

OpenStudy (jango_in_dtown):

9th one is 1/7 , sqrt((n+2)/(49n+2))=sqrt((1+2/n)/(49+2/n))

OpenStudy (itz_sid):

How'd you get that?

OpenStudy (itz_sid):

Why did you divide by n?

OpenStudy (jango_in_dtown):

lim 1/n=0 so to apply this formula i put it in that form

OpenStudy (itz_sid):

Oh i see. thanks! Do you know $8?

OpenStudy (itz_sid):

#8*

OpenStudy (jango_in_dtown):

For 8th one, 4^(n+2)=16 4^n

OpenStudy (jango_in_dtown):

so its basically 16 (4/5)^n

OpenStudy (jango_in_dtown):

4/5 <1 so by its convergent, its basically a GP series

OpenStudy (itz_sid):

how'd you get 16 4^n ?

OpenStudy (jango_in_dtown):

4^(n+2)= 4^n. 4^2 =16. 4^n

OpenStudy (itz_sid):

Got it thanks

OpenStudy (itz_sid):

Can you help me with these? I am stuck :/

OpenStudy (itz_sid):

I got #13.

OpenStudy (itz_sid):

I thought #14 was 1, it wasn't...

OpenStudy (jango_in_dtown):

which one is 13?

OpenStudy (jango_in_dtown):

hello

OpenStudy (itz_sid):

I got #14 as well #13 was 1 #14 was 0

OpenStudy (itz_sid):

I dont get # 12 though

OpenStudy (jango_in_dtown):

12 will be 1

OpenStudy (itz_sid):

How did you get that?

OpenStudy (itz_sid):

Ooooooh. Thanks!

OpenStudy (jango_in_dtown):

lim cos(3/n)=cos (lim3/n)=cos 0 =1

OpenStudy (itz_sid):

OpenStudy (itz_sid):

I needz help with number 18 :3

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