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Mathematics 46 Online
OpenStudy (braydonlevi99):

Help... Please...

OpenStudy (braydonlevi99):

Solve each system by elimination. \[x - y + z = -1\] \[x + y + 3z = -3\] \[2x - y + 2z = 0\]

OpenStudy (3mar):

May I help?

OpenStudy (braydonlevi99):

Go ahead. I'm trying to upload my work to the computer to show what I have done so far.

OpenStudy (3mar):

Thank you.

OpenStudy (3mar):

can you add the eq1 and eq2 together, then eq2 and eq3 together? You will get two eqs with two variables x and z Do it and please share your work

OpenStudy (braydonlevi99):

OpenStudy (braydonlevi99):

There's what I had BEFORE i posted.

OpenStudy (3mar):

@BraydonLevi99

OpenStudy (3mar):

After getting x and z, easily substitute with them in any equation of 1, 2, or 3 You will get y. Congratulations!

OpenStudy (braydonlevi99):

But, in the back of my book it doesn't have those answers.

OpenStudy (agent0smith):

You made a mistake, look at where you worked out z and you'll see it.

OpenStudy (braydonlevi99):

z = -3?

OpenStudy (3mar):

yes z=-3

OpenStudy (braydonlevi99):

Is that correct, @agent0smith ?

OpenStudy (agent0smith):

Yes

OpenStudy (braydonlevi99):

Okay, now what do I do?

OpenStudy (agent0smith):

Finish.

OpenStudy (3mar):

x then y

OpenStudy (braydonlevi99):

Sub z into which equation?

OpenStudy (3mar):

4 or 5 or 6 or 7

OpenStudy (agent0smith):

Whichever one allows you to find something.

Directrix (directrix):

If z = -3 and x = 4, solve for z. @BraydonLevi99

OpenStudy (braydonlevi99):

Directrix (directrix):

Correct.

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