Mathematics
46 Online
OpenStudy (braydonlevi99):
Help... Please...
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OpenStudy (braydonlevi99):
Solve each system by elimination.
\[x - y + z = -1\]
\[x + y + 3z = -3\]
\[2x - y + 2z = 0\]
OpenStudy (3mar):
May I help?
OpenStudy (braydonlevi99):
Go ahead.
I'm trying to upload my work to the computer to show what I have done so far.
OpenStudy (3mar):
Thank you.
OpenStudy (3mar):
can you add the eq1 and eq2 together, then eq2 and eq3 together?
You will get two eqs with two variables x and z
Do it and please share your work
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OpenStudy (braydonlevi99):
OpenStudy (braydonlevi99):
There's what I had BEFORE i posted.
OpenStudy (3mar):
@BraydonLevi99
OpenStudy (3mar):
After getting x and z, easily substitute with them in any equation of 1, 2, or 3
You will get y.
Congratulations!
OpenStudy (braydonlevi99):
But, in the back of my book it doesn't have those answers.
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OpenStudy (agent0smith):
You made a mistake, look at where you worked out z and you'll see it.
OpenStudy (braydonlevi99):
z = -3?
OpenStudy (3mar):
yes
z=-3
OpenStudy (braydonlevi99):
Is that correct, @agent0smith ?
OpenStudy (agent0smith):
Yes
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OpenStudy (braydonlevi99):
Okay, now what do I do?
OpenStudy (agent0smith):
Finish.
OpenStudy (3mar):
x
then
y
OpenStudy (braydonlevi99):
Sub z into which equation?
OpenStudy (3mar):
4 or 5 or 6 or 7
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OpenStudy (agent0smith):
Whichever one allows you to find something.
Directrix (directrix):
If z = -3 and x = 4, solve for z.
@BraydonLevi99
OpenStudy (braydonlevi99):
Directrix (directrix):
Correct.