Mathematics
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OpenStudy (erod0):
Simplify tan^2theta+1
---------------
sec^2theta
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OpenStudy (3mar):
May I help?
OpenStudy (erod0):
\[\frac{ \tan^2\theta+1}{ \sec^2\theta }\]
OpenStudy (erod0):
yes plz
OpenStudy (3mar):
Thank you.
OpenStudy (3mar):
Are you familiar with trigonometric identities?
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OpenStudy (3mar):
Can you kindly respond more faster, please?
OpenStudy (3mar):
@erod0
OpenStudy (3mar):
You are funny!
The asker asked and walk away!
He would take the answer by delivery!
OpenStudy (erod0):
lol wait im sorry
OpenStudy (erod0):
no im not familiar with trigonometric identities
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OpenStudy (3mar):
I was waiting for you
OpenStudy (erod0):
i was in the bathroom
OpenStudy (3mar):
Ok
No problem.
OpenStudy (3mar):
\[\tan \theta=\frac{ ? }{ ? }\]
OpenStudy (erod0):
i have no idea
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OpenStudy (3mar):
\[\tan \theta=\frac{ \sin \theta }{ \cos \theta }\]
right?
OpenStudy (3mar):
@erod0
OpenStudy (3mar):
Can you kindly respond more faster, please?
OpenStudy (erod0):
yes
OpenStudy (erod0):
ok im sorry i was peeing
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OpenStudy (3mar):
\[(\tan \theta)^2=??\]
OpenStudy (erod0):
is it 1?
OpenStudy (3mar):
Yes it is 1
but you know why or it is just guess?
OpenStudy (erod0):
i remember it from my lecture
OpenStudy (3mar):
So why ""no im not familiar with trigonometric identities""??
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OpenStudy (erod0):
well im somewhat familiar with them
OpenStudy (3mar):
You did say that.
I thought you are in grade 6 or 8!
OpenStudy (erod0):
im in college lol
OpenStudy (3mar):
So you should know it very very well!!
OpenStudy (erod0):
no not quite. please what is the answer?
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OpenStudy (3mar):
The answer is 1 as you and I said!
OpenStudy (3mar):
Got it?
OpenStudy (3mar):
@erod0
OpenStudy (erod0):
yes thank u!
OpenStudy (3mar):
With my pleasure!
You are welcome!