A man pulls a crate with a rope. The crate slides along the floor in the horizontal direction (x direction). The man exerts a force of 50 N on the rope, and the rope is at an angle of .
Data Table:
 (Degrees) Fx (N) Fy(n)
0 50 N 0N
10
20
30
40
50
60
70
80
90 0N 50N
Fx=Fn Cos 
Fy=Fn Sin
Cos= adj/ hyp
hyp=50n
Sin= opp/hyp
Sin hype= opp

Please help this is part of a worksheet that is due today and i really don't understand how to get the answer.

Question

A man pulls a crate with a rope. The crate slides along the floor in the horizontal direction (x direction). The man exerts a force of 50 N on the rope, and the rope is at an angle of .
Data Table:
 (Degrees)     Fx (N)     Fy(n)
0                       50 N       0N
10
20
30
40
50
60
70
80
90                     0N         50N
 Fx=Fn Cos 
Fy=Fn Sin
Cos= adj/ hyp
hyp=50n
Sin= opp/hyp
Sin hype= opp

Please help this is part of a worksheet that is due today and i really don't understand how to get the answer.

m8ykarim · Answer

Let the angle is #. Now Fx=Fcos# and Fy=Fsin#. Just simply put the # and calculate it.