Question

Plese help ive been here for hours!!
In guinea pigs, dark hair (D) is dominant over light hair (d) and curly hair (C) is dominant over smooth hair (c). Complete a dihybrid cross for parents with the genotypes: DdCc × DdCc and answer the following in complete sentences.

Describe how you would set up a Punnett square for this cross.
List the likelihood of each possible offspring genotype.
List the likelihood of each possible offspring phenotype.

Answer 1

give me a sec

Answer 2

thanks

Answer 3

i dont know im not in biology but have you tried to googe it and find like a test prep site that has answers and help for stuff like this

Answer 4

ugh yes

Answer 5

ohh
i might be able to find somethin just give me a sec ima try to help

Answer 6

i pm u with a link go look at it and see if thats what you need

Answer 7

i already saw that but idk how to paraphrase it and i cant plagarise

Answer 8

ohhh well ummm shoot usualy to avoide plagarising i just add alot of extra wording and stuff

Answer 9

First you need to see how the alleles can exist on their own. So FOR DdCc you can get:
DC
Dc
dC
dc
the above alleles is what you do the cross with. In my diagram I will replace small c with u so that it doesn't get confusing, so you are crossing:
DC
Du
dC
du

DDCC 1 = 6.25% Dark curly hair
DDCu 2 = 12.5% Dark curly hair
DdCC 2 = 12.5% Dark curly hair
DdCu 4 = 25% Dark curly hair
DDCu 1 = 6.25% Dark curly hair

DDuu 2 = 12.5% Dark smooth hair

ddCC 1 = 6.25% light curly hair
ddCu 2 = 12.5% light curly hair

dduu 1 = 6.25% light smooth hair

The likelihood/probability of dark curly hair is 62.5%
The probability of dark smooth hair is 12.5%
The probability of light curly hair is 18.75%
The probability of light smooth hair is 6.25