Part B: If (60)x = 1, what are the possible values of x? Explain your answer. (5 points)
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OpenStudy (dabbingpikachu):
Part B: If (6^0)x = 1, what are the possible values of x? Explain your answer. (5 points)
*Correction*
OpenStudy (leenathan):
il that username XD
OpenStudy (dabbingpikachu):
Thank you :D
OpenStudy (leenathan):
ok s0 6 to the power of 0 = 1 so x can be 0
OpenStudy (leenathan):
\[6^0=1\]
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OpenStudy (leenathan):
\[(6^0)x = 1 x ...can..be ..0\]
OpenStudy (kayleerose0715):
its going to be 1/60 becasue your going to divide by 60 on both sides to make it equal so it will look like (60)1/60=1 and thats true 1/60 times 60 equals 1
OpenStudy (leenathan):
ur wrong
OpenStudy (leenathan):
thats not the one were doing
OpenStudy (dabbingpikachu):
IDK WHO TO BELIEVE
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OpenStudy (leenathan):
Part B: If (\[6^0\]x = 1, what are the possible values of x? Explain your answer. (5 points)
*Correction*
OpenStudy (kayleerose0715):
how its a true statement and it says there can be multiple answers
OpenStudy (leenathan):
a number to the power of 0 = 1
OpenStudy (leenathan):
you doing the wrong qustion
OpenStudy (kayleerose0715):
yeah so 60 *1 =60 not 1 its supposed to equal 1
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OpenStudy (leenathan):
\[6^0 *x=1\]
OpenStudy (leenathan):
its not 60
OpenStudy (leenathan):
its \[6^0\]
OpenStudy (leenathan):
that why it has ^ ....6^0
OpenStudy (dabbingpikachu):
SOMEONE JUST SAY WHOSE CORRECT
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OpenStudy (leenathan):
me
zepdrix (zepdrix):
Are you sure the original equation wasn't meant to be this?\[\large\rm (6^0)^x=1\]Just checking.
OpenStudy (leenathan):
im a human calculator and i have 112 fan i obviously am right
OpenStudy (dabbingpikachu):
Yes zepdrix
OpenStudy (leenathan):
then im right
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OpenStudy (kayleerose0715):
so then yeah he would be correct i was solving the original one
OpenStudy (leenathan):
medal plz
OpenStudy (dabbingpikachu):
Bow
OpenStudy (leenathan):
i now have 216 medals!!!!!!!!!!!!!!!
OpenStudy (leenathan):
like 2016
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OpenStudy (dabbingpikachu):
Well now this is full of a bunch of stuff that i have to dig through to find the original answer
OpenStudy (leenathan):
its 0
OpenStudy (leenathan):
x=0
OpenStudy (kayleerose0715):
and btw the followers dont mean that your smarter im doing college algebra 2 years ahead of what my class actually is supposed to do this year please do not use followers as an excuse
OpenStudy (leenathan):
\[6^0 * x =1 \] x = 0
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OpenStudy (leenathan):
oh nice but im mostly correct
OpenStudy (kayleerose0715):
yes i didnt realize there was a correction i thought there were two different questions to answer i was answering the first one before i got to the second one