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Mathematics 15 Online
OpenStudy (bonnieisflash1.0):

need help simple math

OpenStudy (bonnieisflash1.0):

@OpenStudyRocks5*

DivineSolar (divinesolar):

Problem?

OpenStudy (bonnieisflash1.0):

sí amigo

DivineSolar (divinesolar):

¿Cuál es el problema?

OpenStudy (bonnieisflash1.0):

Let f(x) = √(x - 4) + 3. a) Find the inverse of f. b) Find the range of f -1.

OpenStudy (bonnieisflash1.0):

Let h(x) = (x - 1) / (-x + 3). a) Find the inverse of h. b) Find the range of h. Let f(x) = (x - 1)/(x + 5) and g(x) = 1/(x + 3). a) Find the composite function (f o g)(x). b) Find the domain of f o g.

OpenStudy (bonnieisflash1.0):

justo ahí

OpenStudy (bonnieisflash1.0):

@OpenStudyRocks5*

OpenStudy (bonnieisflash1.0):

dime cuando planees sabes

DivineSolar (divinesolar):

Primero parte > f(x) = inverse = N/A b) > Range > f(x) > 3

OpenStudy (bonnieisflash1.0):

@OpenStudyRocks5*

DivineSolar (divinesolar):

Segunda parte > a) > x - 1/-x + 3(-x + 3) = y(-x + 3) < Multiplicar ambos lados Refinar! x - 1 = y(-x + 3) Resolver! x - 1 = y(-x + 3) x - 1 = -yx + 3y Añadir una ambos lados x - 1 + 1 = -yx + 3y + 1 > Refinar > x = -yx + 3y + 1 yx añadir a ambos lados x + yx = -yx + 3y + 1 + yx > Refinar > x + yx = 3y + 1 Factor x + yx x(y + 1) = 3y + 1 Dividir ambos lados por uno x(y + 1)/y + 1 = 3y + 1/y + 1 > Refinar > x = 3y + 1/y + 1 Sustituir y = x > 3x + 1/x + 1 < Inverse

DivineSolar (divinesolar):

b) f(x) < -1 or x > -1

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