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OpenStudy (bonnieisflash1.0):
@OpenStudyRocks5*
DivineSolar (divinesolar):
Problem?
OpenStudy (bonnieisflash1.0):
sí amigo
DivineSolar (divinesolar):
¿Cuál es el problema?
OpenStudy (bonnieisflash1.0):
Let f(x) = √(x - 4) + 3.
a) Find the inverse of f.
b) Find the range of f -1.
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OpenStudy (bonnieisflash1.0):
Let h(x) = (x - 1) / (-x + 3).
a) Find the inverse of h.
b) Find the range of h.
Let f(x) = (x - 1)/(x + 5) and g(x) = 1/(x + 3).
a) Find the composite function (f o g)(x).
b) Find the domain of f o g.
OpenStudy (bonnieisflash1.0):
justo ahí
OpenStudy (bonnieisflash1.0):
@OpenStudyRocks5*
OpenStudy (bonnieisflash1.0):
dime cuando planees sabes
DivineSolar (divinesolar):
Primero parte > f(x) = inverse = N/A
b) > Range > f(x) > 3
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OpenStudy (bonnieisflash1.0):
@OpenStudyRocks5*
DivineSolar (divinesolar):
Segunda parte >
a) > x - 1/-x + 3(-x + 3) = y(-x + 3) < Multiplicar ambos lados
Refinar!
x - 1 = y(-x + 3)
Resolver!
x - 1 = y(-x + 3)
x - 1 = -yx + 3y
Añadir una ambos lados
x - 1 + 1 = -yx + 3y + 1 > Refinar > x = -yx + 3y + 1
yx añadir a ambos lados
x + yx = -yx + 3y + 1 + yx > Refinar > x + yx = 3y + 1
Factor x + yx
x(y + 1) = 3y + 1
Dividir ambos lados por uno
x(y + 1)/y + 1 = 3y + 1/y + 1 > Refinar > x = 3y + 1/y + 1
Sustituir y = x > 3x + 1/x + 1 < Inverse