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5x+17_>7 a.x.>2b.x<2 c.<-2 d.x>-2
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\[5x+17\ge7\] Like this?
yes
Alright so subtract \(17\) \[\ 5x+17−\color{red}{17}≥7−\color{red}{17}\] \[\ 5x≥−10\]
So than divide by \(5\)\[\frac{ 5x }{ 5 }=\frac{ -10 }{ 5}\] each side..you can do one
So when you divide (-10\) by \(5\) your answer would be \(2\) \(\ x≥−2\) would be your answer
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Bruhh why did you change the top of your question? .-.
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