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Mathematics 21 Online
OpenStudy (leea1123):

5x+17_>7 a.x.>2b.x<2 c.<-2 d.x>-2

alones (alones):

\[5x+17\ge7\] Like this?

OpenStudy (leea1123):

yes

alones (alones):

Alright so subtract \(17\) \[\ 5x+17−\color{red}{17}≥7−\color{red}{17}\] \[\ 5x≥−10\]

alones (alones):

So than divide by \(5\)\[\frac{ 5x }{ 5 }=\frac{ -10 }{ 5}\] each side..you can do one

alones (alones):

So when you divide (-10\) by \(5\) your answer would be \(2\) \(\ x≥−2\) would be your answer

alones (alones):

Bruhh why did you change the top of your question? .-.

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