Question

x^2-6x+9=0 a,1 real solution
x^2-3x+15=0 b,2 real solution
c,no real solution
x^2-8x+7=0

Answer 1

If I may help?

Answer 2

@Yonatanbesrat

Answer 3

For the last number, (9, 15 and 7) is there a variable next to them? If they all have a variable here is the answer:
So the answer will be zero for all variables, because all of the numbers have a coefficient and they are all equal to zero.

Answer 4

That's one answer.

Answer 5

Check the discriminant:
\[ax^2+bx+c=0\implies \Delta=b^2-4ac\]There are three cases to consider:
\[\begin{cases}\Delta>0\implies 2\text{ real solutions}\\[1ex]\Delta=0\implies1\text{ real solution}\\[1ex]\Delta<0\implies 2\text{ complex solutions}/0\text{ real solutions}\end{cases}\]