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5n-3(n-6) >= 0
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Could I help you?
yes, please.
First distribute the `3` into the paranthesis `(n-6)`. \(\huge\bf{5n+(-3\times n +6 \times 3) \ge 0}\)
I got 5n-3n-18>=0 Would that be correct?
Correct :) Though it would `+18` not `-18` Now combine like terms... \(\huge\bf{\color{red}{5n-3n}{+18\ge0}}\)
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So would the answer be \[n \ge -9\]?
Nice ;)
Thank you!
No problem :)
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