Question

Help on this 2part question

Answer 1

I do believe we would input the points according to the question.

\(\Large\bf{(h,v) \rightarrow (2,-2)}\)

\(\huge\bf{y=a(x-2)^{2}+(-2)}\)

Then we input the points it needs to go through so the format of a point is \(\large{(x,y)}\)so we input the point given.

\(\huge\bf{\color{red}{-1}=a({\color{red}{3}-2)^{2}+(-2)}}\)

Simplify :)

Answer 2

So `(3-2)` equals `1` in which we would square it which would still equal 1.

\(\huge\bf{-1=a(1)+(-2)}\)

Simplify.

\(\huge\bf{-1=a-2}\)

In which we would add 2 to each side to isolate `a`.

\(\huge\bf{a = 1}\)

Answer 3

and then part 2?

Answer 4

I do believe it is written as.

\(\huge\bf{y=1(x-2)^{2}+(-2)}\)

Answer 5

Thank you once again.