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Mathematics 17 Online
OpenStudy (weaver):

http://prntscr.com/d1geqt How do I solve this?

OpenStudy (weaver):

@Mehek14

OpenStudy (weaver):

@3mar

Vocaloid (vocaloid):

plot the points on a graph and use the distance formula to calculate each side

OpenStudy (3mar):

You have two way to accomplish that!

OpenStudy (3mar):

1. Plot them and look at the rectangle and calculate the length and the width from the graph 2. Use the general formula to calculate the distance between two points You choose

OpenStudy (weaver):

@3mar Dis I do this correctly? I'm not so good at this...

OpenStudy (3mar):

You will be so good, and excellent also! Allah blesses you.

OpenStudy (3mar):

I think you got the width, which is \[\sqrt{8}=2\sqrt{2}=2.828\] not \[\sqrt{2.828}\] am I right?

OpenStudy (3mar):

and the length would be ???

OpenStudy (weaver):

yes okay I need to solve the length just give me a few minutes please

OpenStudy (weaver):

Would that be the points to solve the length? 0,3 and 4,1?

OpenStudy (3mar):

Yes they are the points related to the length of the rectangle!

OpenStudy (3mar):

The length is usually greater than the width!

OpenStudy (weaver):

I got 5.65 for the length

OpenStudy (3mar):

Why? where are your steps, please?

OpenStudy (weaver):

√(4-0)^2+(3-1)^2 √(4)^2+(4)^2 √16+16 √32 √5.65

OpenStudy (3mar):

√(4)^2+(4)^2???? I think you may revise that!

OpenStudy (3mar):

Thank you for the medal!

OpenStudy (weaver):

4x4=16+4x4=16

OpenStudy (3mar):

√(4-0)^2+(3-1)^2 √(4)^2+(4)^2 Does that lead to this?

OpenStudy (3mar):

Mam, do you follow?

OpenStudy (weaver):

oohhh yes i see thank you for correcting me

OpenStudy (3mar):

You are welcome! At your service!

OpenStudy (weaver):

Okay so..√(4-0)^2+(3-1)^2 √(4)^2+(2)^2 √16+4 √20 √4.47

OpenStudy (3mar):

\[√20 \neq√4.47\] \[√20 =2\sqrt{5}=4.47\] right?

OpenStudy (weaver):

yes

OpenStudy (weaver):

Do I add 2.82 and 4.47 to find the perimeter then round to the nearest tenth of a unit?

OpenStudy (3mar):

"add 2.82 and 4.47" then double the answer to get the perimeter, hen round to the nearest tenth of a unit. Let me know when you are done!

OpenStudy (weaver):

Okay thanks!

OpenStudy (3mar):

what is the final result if you want to show it?

OpenStudy (weaver):

2.82x4.47=7.29 7.29^2=16.69=17.0

OpenStudy (3mar):

No, Mam! I mean \[2*(4.47+2.82)=2*7.29=14.58\] square units

OpenStudy (3mar):

Did you get it?

OpenStudy (3mar):

Mam, are you still here?

OpenStudy (weaver):

hmm im confused so I do 2*(4.47+2.82)=11.76

OpenStudy (3mar):

4.47+2.82=7.29 7.29*2=14.58 Easy I think.

OpenStudy (weaver):

oohh okay what do i do next?

OpenStudy (3mar):

Sorry we did a mistake for the length \[length=\sqrt{(-1-3)^2+(4-0)^2}=\sqrt{(-4)^+4^2}=\sqrt{16+16}=4\sqrt{2}=5.657\] Now : (5.657+2.82)*2=16.97~17

OpenStudy (weaver):

oh so 17.0 is correct? :)

OpenStudy (3mar):

Congratulations! ♥ You hit the right target! Happy for that!

OpenStudy (weaver):

Okay thanks so much!!

OpenStudy (3mar):

I apology for confusion I did it to you!

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