Question

6^5x=20 round to the nearest ten-thousandth
(gradpoint)

Answer 1

First, you have to rewrite the equation in logarithm form, as shown here:

log base 6 (20)=5x

Now, we perform a change of base:

log 20 / log 6 = 5x

Then we simply solve the rest:

1.301 / .778 = 5x

1.672 = 5x

.3344 = x

So you final solution, rounded to the nearest ten thousandth is 0.3344.

Answer 2

thank you so much ! you have no idea how much i am struggling with this course

Answer 3

urwelcome