Question

Write a function that has a vertex of (2,4) and contains the point (4,16)

Answer 1

hello so take a parabola

Answer 2

i got y=3(x+2)^2+4

Answer 3

your basic parabola with slope m has form
y=mx^2
if u want to move it to ur vertex
y-4 = m(x-2)^2

now if u will pick an m such that your point is satisfied

Answer 4

its x-2 not x+2, x+2 will make it shift to -2

Answer 5

ok, is everything else good?

Answer 6

k find slope now

Answer 7

y-4 = m(x-2)^2
point (4,16) exists on parabola
16-4=m(16-2)^2
solve for m

Answer 8

3?