Question

cosϴ=-√3 sin(-ϴ)

HELP NOW PLEASE!!!

Answer 1

if you wish to solve for theta best thing to do is to generate the tan ratio

\[\frac{ \sin \theta }{ \cos \theta } = \tan \theta\]

Also note that sin is an odd function so
\[\sin(- \theta) = - \sin(\theta)\]

Use the combination to generate an equivalent equation in tan.