Two bugs are sitting on a turntable, going around with the record at 33 1/3 RPM. One bug sits 3.390 x 10^-2 m from the point of rotation; the other sits 2.540 x 10^-2 m meters from the point of rotation. If the first bug has a tangential speed of 7.5 cm/s, what is the rotational speed of the second bug?
@harman.singh
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can you give me an equation that i can do please?
:( forget this equation pls
what equation?
whatever he's giving u
you know about circles, and its perimeter right, thats all u need to know
ok well can you give me an equation please if his isnt right
his equation is right, nothing wrong with it
I just want you to understand the basics here
okay so 7.5 cm/s is the speed of the bug, in 1 minute, we've rotated 33+1/3 times right
right
so that means uve gone around the circle or the perimeter of that circle wher the bug is at a total of 33+1/3 times
now if u go 7.5 cm /s how many cm is that in 60 secs aka a min
450
right
anyway this is just me trying to make u think about whats going on here
now lets look at the 2nd bug
2.540 x 10^-2 m, so how much perimeter is that for 33 +1/3 rotations
radius is 2.540 x 10^-2 m, what is the total perimeter in 33+1/3 rotations?
254
k the distances are different as u can see so the tangential speed is different
how about rotation? rotation is how much angle has changed about the point of rotation
rev/second is a rotational speed
we started with 33rev/min , and thats the same at all radius away
so how many rev is that in 1 sec
.55
yeah
thats all there is to it
im guessing ur questions continues to ask about the bugs tangential speeds and stuff next?
ok so what would the answer though 44.4 RPM 25 RPM 33 1/3 RPM 66 2/3 RPM c? and yes that is the next question
33 1/3 RPM
the rotational speed has not changed
its the tangential speed that changes
ok can you help me with this one? Two bugs are sitting on a turntable, going around with the record at 33 1/3 RPM. One bug sits 3.390 x 10^-2 m from the point of rotation; the other sits 2.540 x 10^-2 m meters from the point of rotation. If the first bug has a tangential speed of 7.5 cm/s, what is the tangential speed of the second bug? 16.00 cm/s 5.625 cm/s 3.750 cm/s 10.01 cm/s
you should be able to do this now
we found the perimeter it was travelling in total in that min remember
254?
let me see
2pi*R = ? tell me right units
wait what is the radius again
2.540 x 10^-2 m
ok 254 times (2 pi)=1595.12
units?
im not sure
centimeters..
oh ok so 1595.12 cm
does it make sense why its centimeter?
yes
circumference is the perimeter but ok
yes sorry
a circle has 2pi the proportion of the radius
now that is the perimeter for 1 revolution right
how many revolutions are we travelling here for 1 second
from your rotational speed
you found this earlier too
33 1/3rpm
what does rpm stand for
rotations per minute
okay so how many rotations per sec is this
.55
right keep units pls
rps
0.55 rotations per sec
now so how much length is this for us
1 rotation we saw was 1595.12 cm
0.55 rotation =?
1 second
what length is int 0.55 rotation
1 rot = 1595.12 cm 0.55 rot = ________ cm
877.316 cm
yes
since we went 0.55 rot in 1 sec We also went 877.316 cm in 1 sec
and the heck that makes no sense--.- they messed up some numbers or something
ok so what would the answer be out of these choices 16.00 cm/s 5.625 cm/s 3.750 cm/s 10.01 cm/s
Two bugs are sitting on a turntable, going around with the record at 33 1/3 RPM. One bug sits 3.390 x 10^-2 m from the point of rotation; the other sits 2.540 x 10^-2 m meters from the point of rotation. If the first bug has a tangential speed of 7.5 cm/s, what is the tangential speed of the second bug?
well i wasnt gonna go straight to this but, evnetually u wud have found out that really all that matters is the proportion of the radius here
2.54/3.39 * 7.5=?
5.619cm/s?
nothign is wrong, the radius is 2.54 cm not 254 cm
but yes
so the closest is 5.625 cm/s
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