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OpenStudy (aaronandyson):
Optics helped!
No one?
OpenStudy (vijeya3):
O_O
OpenStudy (aaronandyson):
Question tuh type kar!
OpenStudy (vijeya3):
A person wears glasses of power -2.5 D .What is the far point of the person without the glasses?
OpenStudy (aaronandyson):
you have this in 10th? O_O
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OpenStudy (vijeya3):
yeah
why ya had this in 5th?
OpenStudy (aaronandyson):
No.
I had this in LKG.
OpenStudy (vijeya3):
LOL Maharashtra is super advanced then...so u must know it like ABC so tell me. how do we do it sir?
OpenStudy (aaronandyson):
What are the options?
OpenStudy (vijeya3):
no options..
It's HCV question buddy
But nonetheless I'll make them up for you..
10 cm
30 cm
50cm
40cm
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OpenStudy (vijeya3):
yep
OpenStudy (aaronandyson):
I think its 1/-2.5
OpenStudy (aaronandyson):
Not really sure...havent mastered this topic as yet..
OpenStudy (vijeya3):
but that wouldn't give us 40 cm....it would be 4 m:'(
OpenStudy (vijeya3):
@mayankdevnani
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OpenStudy (aaronandyson):
Ayyy fam x'D
OpenStudy (mayankdevnani):
40 cm ?
OpenStudy (vijeya3):
yeah mayday
OpenStudy (mayankdevnani):
is it correct ?
OpenStudy (vijeya3):
yeah
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OpenStudy (aaronandyson):
*hears the bell ringing* :)
OpenStudy (vijeya3):
:o
what bell?
like school bell?x'D
OpenStudy (aaronandyson):
school ka ghanta nah be
OpenStudy (vijeya3):
abey toh kahe k ghnta?/
@mayankdevnani how didja get it?
OpenStudy (aaronandyson):
aye chori
kahe aisi Hindi m bat kar ti re ,huh?
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OpenStudy (vijeya3):
oye chore
hmri hindi esi hi haigi....hum gao mein rhet hain...x'D
OpenStudy (vijeya3):
mayank bhaiya suspense khol bhi do ab
OpenStudy (aaronandyson):
abe minku tu kabse type kar rha h
essay likh rha h kya?
OpenStudy (mayankdevnani):
we have given power
so we can easily find focal length
negative sign means it's near sightedness ig
use lens formula :-
\[\large \bf \frac{1}{v}-\frac{1}{u}=\frac{1}{f}\]
u is technically `zero`cuz we gotta find far point so initially we take u as our initial position
so,after plugging u=0,we get
v=f=40 cm(excluding sign)
OpenStudy (mayankdevnani):
Hope it helps :)
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OpenStudy (aaronandyson):
1/u
if u = 0 then the expression is infinity ...kab kya
OpenStudy (aaronandyson):
okay samjha
lens makers equations
OpenStudy (mayankdevnani):
flutter :(
OpenStudy (vijeya3):
Okay so u are trying to say that we consider the object to be at infinity?
OpenStudy (mayankdevnani):
bhai galat likh diya :(
far point means infinity
so 1/v tends to zero
so -1/u=1/f
u=-f
u=40 cm
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OpenStudy (aaronandyson):
lifesaver saving your life as always ;)
OpenStudy (vijeya3):
I was doing the same thing but ig there was some calc problem
thanks anyway:)