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OpenStudy (esa_pau):
Determine which of the given numbers are roots of the polynomial f(x)= 6x^2+x-1
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OpenStudy (esa_pau):
a. 1/2, 1
b.-1/2,2
c. -1/2
d. 1
i know its not B
OpenStudy (vuriffy):
Just plug them in and try.
OpenStudy (vuriffy):
6x^2+x-1 = 0
Let's try -1/2
6(-1/2)^2-1.5 = 0
6(1/4) - 1.5 = 0
1.5 - 1.5 = 0.
That means it is a solution.
OpenStudy (vuriffy):
-1/2 - 1 = - 1.5, by the way.
OpenStudy (vuriffy):
0 = 0.
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OpenStudy (esa_pau):
alright got it thanks
OpenStudy (vuriffy):
Sweet, great job.
OpenStudy (sshayer):
\[6x^2+3x-2x-1=3x(2x+1)-1(2x+1)=(2x+1)(3x-1)\]
2x+1=0
x=-1/2
3x-1=0
3x=1
x=1/3
from here you can see your option.
OpenStudy (esa_pau):
u lost me
OpenStudy (vuriffy):
The polynomial had two solutions, but your question only gave one of them, which is why I only demonstrated one, whereas @sshayer did both.
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OpenStudy (esa_pau):
ahh so it just gave me half an answer in the multiple choice?
OpenStudy (vuriffy):
Technically, yes, it did. But, you only need the one which had -1/2, so it was okay.
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