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OpenStudy (imterribleatmath):
@Will.H
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OpenStudy (will.h):
1st we need to find k 1200 = 1000e^k2 Solve for k e^2K = 1.2 K2 = in (1.2) K = 0.0911607784 Now substitute that in the exponential form And solve when t= 13 P = 1000e^0.0911607784*13 P=3270.98 To the nearest whole number would be 3271
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