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OpenStudy (jango_in_dtown):
@Kevin
OpenStudy (kevin):
hmm... but how do you not eliminate (a) in A?
A-B = {a, b, {a, c}, ∅} - {a, {a}, d, e}
Sorry, I still understand this part
OpenStudy (jango_in_dtown):
a and {a} are not the same
OpenStudy (kevin):
what is the difference?
OpenStudy (jango_in_dtown):
a is an element. and {a} is a set
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OpenStudy (kevin):
so, is there any set of a in A?
OpenStudy (kevin):
I'm thinking to eliminate a from {a, c} in A. But that's not right, right?
OpenStudy (jango_in_dtown):
While evaluating A-B, you need to look at those elements of A, which are not in B . Those will give the answer.
No {a} and {a,c} are again different sets. You cannot cancel.
OpenStudy (kevin):
I see, thx.
I still have same question
OpenStudy (jango_in_dtown):
Which question? . :)
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OpenStudy (kevin):
B²
OpenStudy (jango_in_dtown):
B*B? Its the cartesian product
OpenStudy (kevin):
Should I write the element twice?
OpenStudy (kevin):
still have no clue
OpenStudy (jango_in_dtown):
No B*B ={(b,b) b belongs to B}
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OpenStudy (jango_in_dtown):
Let me give you an example
Let B={1,2}
Then B*B={(1,1),(1,2),(2,1),(2,2)}
OpenStudy (kevin):
I see now :)
OpenStudy (kevin):
Wait, should it be like power set?
OpenStudy (jango_in_dtown):
No. Power set will contain all subsets.. Let me tell you how to compute B*B.
OpenStudy (kevin):
Like this?
|dw:1478540676229:dw|
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