I need help about math set
@mathmate
...yes?
If A = {a, b, {a, c}, ∅} and B = {a, {a}, d, e}, Then: A - ∅ ?
@zepdrix @563blackghost @inkyvoyd
Hint: Link will give answer AND explains why. Be sure to read the proof! https://proofwiki.org/wiki/Set_Difference_with_Empty_Set_is_Self
which one is it?
∅ is also part of A. That's make me confused :s
Hi @Loser66 Would you help me?
if your family has you, your mom, your dad and your sister what is the family member without you?
So, it's a, b, {a, c} ?
Dat sit
Next question, A - {∅}
Hi @jango_IN_DTOWN Would you help me?
what is the question?
If A = {a, b, {a, c}, ∅} and B = {a, {a}, d, e}, Then: a. A - ∅ ? b. A - {∅} ?
A-∅ =A A-{∅ }={a, b, {a, c}} In the first case ∅ is the empty set In the second case {∅} this set is deducted from A
Thx! I need more help
/post in a new thread .
Ok :(
but it's still same question
okay
c. { {a, c} } - A It's ∅ right?
correct
{a} - {A} I don't understand this one
/i guess it will be ∅ again
Next question, P (A - B)
We supposed to count elements?
What does P(A) stands for here?
That's it, I don't understand
Generally P stands for probability,
But not here
maybe power set
Oh yeah, but it has a different symbol. :) like P, but not P. ok..
So tell me what is A-B here?
Here is the example If A = {1, 2}, Then P(A) = {∅, {1}, {2}, {1, 2}}
That's it, I guess A-B = {a, b, {a, c}, ∅} - {a, {a}, d, e} A-B = {b, {c}, ∅} Pls check it again, coz I really don't understand with this
A-B contains those elements of A which are not in B.. TRy once again finding A-B
Hmmm,, what is it?
Do one by one, first take the element a of A. Is it in B? The answer is yes. So we cannot include a in A-B.. Do similarly and give me the answer
Well let me write it, you check if I am correct A-B={ b, {a, c}, ∅}
Now take the power set. It will give the answer
Power set is the set of all possible subsets which can be formed using this set A-B
It will contain 2^3=8 elements
P(A-B)={b,{a,c},∅,{b,{a,c}},{b,∅},{{a,c},∅},{ b, {a, c}, ∅}}
see we got 8 elements Bingoooo
@Kevin
hmm... but how do you not eliminate (a) in A? A-B = {a, b, {a, c}, ∅} - {a, {a}, d, e} Sorry, I still understand this part
a and {a} are not the same
what is the difference?
a is an element. and {a} is a set
so, is there any set of a in A?
I'm thinking to eliminate a from {a, c} in A. But that's not right, right?
While evaluating A-B, you need to look at those elements of A, which are not in B . Those will give the answer. No {a} and {a,c} are again different sets. You cannot cancel.
I see, thx. I still have same question
Which question? . :)
B²
B*B? Its the cartesian product
Should I write the element twice?
still have no clue
No B*B ={(b,b) b belongs to B}
Let me give you an example Let B={1,2} Then B*B={(1,1),(1,2),(2,1),(2,2)}
I see now :)
Wait, should it be like power set?
No. Power set will contain all subsets.. Let me tell you how to compute B*B.
Like this? |dw:1478540676229:dw|
. :)correct/
|dw:1478540828043:dw|
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