Question

−a^2 − 3b^3 + c^2 + 2b^3 − c^2 if a = 3, b = 2, and c = −3

Answer 1

Just plug in the values of the variables and solve.

Answer 2

-3^2-32^3+-3^2+22^3- -3^2

Answer 3

it dose not look right.

Answer 4

You need to solve it. What is -3^2 ?

Answer 5

-9

Answer 6

Next one is -3(2)^2

Answer 7

here are the options
−67
−17
−31
1

Answer 8

You need to multiply not make it a whole new number

Answer 9

sorry -3(2)^3

Answer 10

so 361?

Answer 11

ohh wait

Answer 12

6859?

Answer 13

2^3 then multiply by -3

Answer 14

actually I think you could multiply the -3 and 2 then cube it

Answer 15

-24

Answer 16

Yes

Answer 17

Then do the next one

Answer 18

so -9

Answer 19

no just 9 because the - is included

Answer 20

-3 times -3

Answer 21

positive 9

Answer 22

so now -9-24+9

Answer 23

-24

Answer 24

Okay lets try the 3(2)^3 again but this time multiply 3 and 2 then cube it

Answer 25

64?

Answer 26

Never mind sorry, I didnt see there was two more left to do we need to find the values for. Okay so now do the 2(2)^3 like we did before

Answer 27

64

Answer 28

No, 2^3 then multiply by 2

Answer 29

16

Answer 30

is the answer 1

Answer 31

Hold on let me do the math for a second. I forget whether you do the power first or you multiple first then the power

Answer 32

Okay no we are doing it right. No it is not 1

Answer 33

okay so now -(-3)^2 what is that?

Answer 34

+9

Answer 35

No try again. Remember (-3)^2 was?

Answer 36

-9

Answer 37

Okay, what about the 2(2)^3

Answer 38

18

Answer 39

No, 2^3 is what?

Answer 40

16 sorry

Answer 41

There you go, now let's put it all together

Answer 42

-9-24+9+16-9

Answer 43

-17

Answer 44

Yes! Good job!

Answer 45

thx!!!