Question

Can someone tell me if my steps are correct or not?
"Solve the following system of equations:
3p-2q+2r=1
-2p+q-3r=2
3p-4q+3r=-7

Answer 1

Just reply to this if you can. :)

Answer 2

May I help?

Answer 3

Of course.

Answer 4

I wanted to answer using substitution.

Answer 5

Thank you.

Can you share your works/steps, please?

Answer 6

So I made q=2+2p+3r
I plugged it in for the first equation and got:
3p-2(2+2p+3r)+2r=1
3p-4-4p-6r+2r=1
-p=-5-4r
p=-5-4r

Answer 7

you prefer sub. or ele.?

Answer 8

Sub.

Answer 9

Yes. I see!

Answer 10

Then for the third equation, I plugged in for q and got
3p-4(2+2p+3r)+3r=-7
-5p-9r=1

Answer 11

I plugged in for p for -5p-9r=1 and got
-5(-5-4r)-9r=1
25+11r=1
r=(-24/11)

Answer 12

Good so far?

Answer 13

You still here?

Answer 14

p=-5-4r
-5p-9r=1

\[\checkmark\]

Answer 15

I was checking one-by-one

r=(-24/11)

then sub. to get q and p...what are their values?

Answer 16

I got q=(32/11)
and p=41/11

Answer 17

\[\Huge\color{greenyellow}\checkmark\]

Excellent!

Answer 18

If there are any more questions, pleasure is mine to help!

Answer 19

Nicely Done @Seratul

Answer 20

Thank you for the medal!
You are Excellent!

Answer 21

My bad @3mar I had to go get something from the store. Thanks for the help!

Answer 22

No problem at all!
You are welcome!
Any Help... Any Time...