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\[\large{x^{a}\times x^{b}=x^{(a+b)}}\]
\(x=7\), \(a=3\) and \(b=-5\) in this case. Replace and solve
ugh I keep getting D but its incorrect....
3+(-5)=?
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2?
Close.
3!
cause -5 is 0 and +3 is 3
LMAO OH
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