Question

precal question: please help!!

Answer 1

Have you a plan for solution? Frankly, graphing might be the most helpful.

Answer 2

No, I have no idea what to do or how to start.

Answer 3

This question is quite tripping me up too!

Answer 4

\(\log_{a}(x) = 0\), when x = 1 and a > 0.

You may wish to consider something around x+3 = 1.

Answer 5

Sorry I typed that wrong

Use
log(base 2) 16 = 4 2^4 = 16
log(base) [Y] = X base^X = Y

0.75^(x+3) = Y1 > Y2 = 0.05^(x+3) plot these two equations