Question

A species of extremely rare, deep water fish are slowly becoming extinct. If there are a total 821 of this type of fish and there are 15% fewer fish each month, how many will there be in half a year?

Answer 1

what do u think it is?

Answer 2

hello

Answer 3

821(1+.15)^6

Answer 4

is there answer?

Answer 5

no

Answer 6

@3mar

Answer 7

ok in not 100% sure

Answer 8

sorry

Answer 9

Well, I am here.
That is with my pleasure to help you!

Answer 10

@shaleiah

Still need help?

Answer 11

yes

Answer 12

With my pleasure!
Where are you stuck exactly?

Answer 13

Is this the proper formula to find the growth? 821(1+.15)^6?

Answer 14

there are 15% "fewer" fish each month or "more"?

Answer 15

"find the growth? 821(1+.15)^6?"
are you going to find the growth or decay!?!?!

Answer 16

decay

Answer 17

821(1-.15)^6

Answer 18

So That makes sense now!

Answer 19

309.64?

Answer 20

\[\Huge\color{Lime }\checkmark\]

That is to be more sure, sister!
https://www.desmos.com/calculator/irz896juq1

Answer 21

https://www.desmos.com/calculator/gdq6ibzyok

That is the fish numbers in the 6th month!

Answer 22

Thank you for the medal!
I appreciate!